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What is the process for printing a rhomboid shape using Python?

asked 2023-06-01 06:51:50 +0000

devzero gravatar image

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answered 2023-06-01 07:09:01 +0000

qstack gravatar image

Here is an example code to print a rhomboid shape using Python:

# define the size of the rhomboid
size = 5

# loop through the rows
for i in range(size):

    # print spaces before each row
    print(" " * (size - i - 1), end="")

    # print the row
    for j in range(size):
        print("* ", end="")

    # move to the next line
    print()

# loop through the rows in reverse order
for i in range(size - 1, 0, -1):

    # print spaces before each row
    print(" " * (size - i - 1), end="")

    # print the row
    for j in range(size):
        print("* ", end="")

    # move to the next line
    print()

This code uses two loops to print the top and bottom halves of the rhomboid shape. The size of the rhomboid is defined at the beginning, and the loops are used to print the correct number of spaces and asterisks on each row. The end="" statement is used to prevent the print function from moving to a new line after each row.

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Asked: 2023-06-01 06:51:50 +0000

Seen: 16 times

Last updated: Jun 01 '23