Here are a few ways to make the multiplication process between a sparse matrix and a dense ndarray vector in SciPy faster:
Use the dot
method instead of the *
operator:
The dot
method is usually faster than the *
operator when multiplying a sparse matrix and a dense vector in SciPy. For example:
import numpy as np
from scipy.sparse import csr_matrix
# Create a random sparse matrix in CSR format
shape = (10000, 10000)
density = 0.01
sparse_mat = csr_matrix(np.random.rand(*shape) < density)
# Create a random dense vector
dense_vec = np.random.rand(shape[1])
# Multiply the sparse matrix and dense vector using dot method
result = sparse_mat.dot(dense_vec)
This method uses more efficient algorithms for matrix multiplication and can be significantly faster than the *
operator.
Use a more efficient sparse format:
Some sparse formats are more efficient than others for certain operations. For example, the Compressed Sparse Row (CSR) format is usually faster than the Compressed Sparse Column (CSC) format when multiplying a sparse matrix and a dense vector. You can convert a sparse matrix to a different format using the tocsr
, tocoo
, tocsc
, or todok
methods. For example:
# Convert the sparse matrix to CSR format
sparse_mat_csr = sparse_mat.tocsr()
# Multiply the sparse matrix in CSR format and dense vector
result = sparse_mat_csr.dot(dense_vec)
This can be faster because the CSR format optimizes for accessing the row indices of the sparse matrix, which is the bottleneck for matrix-vector multiplication.
Use Cython or Numba:
Cython and Numba are tools that can be used to accelerate Python code by generating C or LLVM code, respectively. They can be used to speed up the matrix-vector multiplication operation in SciPy. For example:
import numpy as np
from scipy.sparse import csr_matrix
from numba import njit
# Create a random sparse matrix in CSR format
shape = (10000, 10000)
density = 0.01
sparse_mat = csr_matrix(np.random.rand(*shape) < density)
# Create a random dense vector
dense_vec = np.random.rand(shape[1])
# Multiply the sparse matrix and dense vector using a Numba JIT function
@njit
def matvec(sparse_mat, dense_vec):
result = np.zeros(shape[0])
indptr = sparse_mat.indptr
indices = sparse_mat.indices
data = sparse_mat.data
for i in range(shape[0]):
for j in range(indptr[i], indptr[i+1]):
result[i] += data[j] * dense_vec[indices[j]]
return result
result = matvec(sparse_mat, dense_vec)
This method can be significantly faster because it directly translates the Python code to low-level machine code, bypassing the Python interpreter.
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Asked: 2021-05-12 11:00:00 +0000
Seen: 23 times
Last updated: Apr 11 '23
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