To divide a row into multiple rows depending on the difference in dates, you first need to identify the date range that you want to divide the row into. Then, you can create a loop that iterates through the date range and splits the original row into multiple rows based on the difference in dates. Here's an example of how you can do this using Python:
import pandas as pd
# sample data
data = {'Name': ['John', 'Mary'], 'Start Date': ['2022-01-01', '2022-01-05'], 'End Date': ['2022-01-03', '2022-01-08']}
df = pd.DataFrame(data)
# convert date columns to datetime
df['Start Date'] = pd.to_datetime(df['Start Date'])
df['End Date'] = pd.to_datetime(df['End Date'])
# create empty list to store new rows
new_rows = []
# loop through each row
for index, row in df.iterrows():
# calculate number of days in date range
num_days = (row['End Date'] - row['Start Date']).days
# add original row to list
new_rows.append(row)
# if date range is greater than 1 day, split row into multiple rows
if num_days > 0:
for i in range(1, num_days + 1):
# create new row with updated start date
new_row = row.copy()
new_row['Start Date'] = row['Start Date'] + pd.DateOffset(days=i)
# add new row to list
new_rows.append(new_row)
# create new dataframe with updated rows
new_df = pd.DataFrame(new_rows)
# sort dataframe by name and start date
new_df = new_df.sort_values(['Name', 'Start Date'])
print(new_df)
This code takes a dataframe with columns "Name", "Start Date", and "End Date" and converts the date columns to datetime. It then loops through each row and calculates the number of days in the date range. If the date range is greater than 1 day, it splits the row into multiple rows based on the number of days in the date range. It then creates a new dataframe with the updated rows and sorts the dataframe by name and start date. The output of this code will be a dataframe with the original rows and any additional rows that were added based on the date range.
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Asked: 2021-07-25 11:00:00 +0000
Seen: 14 times
Last updated: Apr 27 '21
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