What is the process for modifying header labels and transforming data rows into columns using a batch file?

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The process for modifying header labels and transforming data rows into columns using a batch file involves the following steps:

1. Identify the input file from which you want to modify header labels and transform data rows into columns.

2. Create a new batch file by opening Notepad or any other text editor.

3. In the batch file, add the command to rename the header labels. For example, if you want to rename the header label "Name" to "Full Name", you can add the following command:

   ren input.csv output.csv
   

   This command will rename the file "input.csv" to "output.csv" and all operations will be performed on the "output.csv"file.

4. Add the command to transform data rows into columns. For Example, If you want to transform "Name, Age, and Gender" into columns and write it to a new file, you can use the following command:

   for /f "tokens=1,2,3 delims=," %%a in (output.csv) do echo %%a,%%b,%%c>>newoutput.csv
   

   This command will iterate over each row of the "output.csv" file, and for each row, the command will break the row into three columns separated by comma and write it to a new file named "newoutput.csv".

5. Save the batch file with an appropriate name, such as "modifyandtransform.bat".

6. Execute the batch file by double-clicking on it or running it from the command prompt.

7. The new file with modified header labels and transformed data rows will be generated as per your requirement.