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What is the process for combining dictionaries that contain other dictionaries?

asked 2022-09-27 11:00:00 +0000

scrum gravatar image

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answered 2021-11-19 00:00:00 +0000

nofretete gravatar image

The process for combining dictionaries that contain other dictionaries is as follows:

  1. Create an empty dictionary to store the resulting combined dictionary.

  2. Loop through all the dictionaries that need to be combined.

  3. For each dictionary, loop through all its keys and values.

  4. If the value of a key is also a dictionary, check if the key already exists in the resulting dictionary. If it does, you need to combine the two dictionaries. If it doesn't, add the key and the dictionary as a new key-value pair in the resulting dictionary.

  5. If the value of a key is not a dictionary, simply add the key-value pair to the resulting dictionary.

  6. After looping through all the dictionaries, the resulting dictionary will contain all the keys and values of all the dictionaries combined.

  7. Return the resulting dictionary.

Example:

def combine_dicts(*dicts):
    result_dict = {}

    for d in dicts:
        for key, value in d.items():
            if isinstance(value, dict):
                if key in result_dict and isinstance(result_dict[key], dict):
                    result_dict[key] = combine_dicts(result_dict[key], value)
                else:
                    result_dict[key] = value
            else:
                result_dict[key] = value

    return result_dict

dict1 = {'a': 1, 'b': {'x': 2, 'y': 3}}
dict2 = {'b': {'y': 4, 'z': 5}, 'c': 6}
dict3 = {'d': 7}

combined_dict = combine_dicts(dict1, dict2, dict3)
print(combined_dict)
# Output: {'a': 1, 'b': {'x': 2, 'y': 4, 'z': 5}, 'c': 6, 'd': 7}

In this example, we defined a function combine_dicts that takes multiple dictionaries as arguments and returns a combined dictionary. The function loops through all the dictionaries and uses the isinstance function to check if a value is a dictionary or not. If it is a dictionary, the function recursively calls itself to combine the dictionaries. If not, it simply adds the key-value pair to the resulting dictionary.

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Asked: 2022-09-27 11:00:00 +0000

Seen: 7 times

Last updated: Nov 19 '21