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What is the outcome of dereferencing Box<T> - does it provide a value or a reference?

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asked 2021-07-18 11:00:00 +0000

pufferfish
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answered 2022-10-22 20:00:00 +0000

huitzilopochtli
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When we dereference a Box<T> using the * operator, we get a value of type T. So, dereferencing a Box<T> provides a value, not a reference.

However, if the value of type T itself contains references, then we would get a reference to the contents of the Box<T> when we access those references from the dereferenced value.

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