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To remove an element from an array in Rust using Leetcode, you can use the Vec<T> data structure and its remove method.

Here's an example code snippet that shows how to remove an element at a given index from an array:

fn remove_element(nums: &mut Vec<i32>, val: i32) -> i32 {
    let mut i = 0;
    while i < nums.len() {
        if nums[i] == val {
            nums.remove(i);
        } else {
            i += 1;
        }
    }
    nums.len() as i32
}

In this function, we're using a while loop to iterate through the array and remove any elements that match the given value val. We're also keeping track of the current index i and incrementing it only when we don't remove an element from the array. Finally, we return the new length of the array as an i32 value.