1 | initial version |
To combine streams of different types in Dartlang using rxdart, you can use the .combineLatest
method or zip
method.
.combineLatest
method: This method merges the latest values emitted by each stream into a new stream. For example, if you have two streams of type int
and String
, and you want to combine them into a new stream with each emitted value as a list [int, String]
, you can use the following code:
import 'package:rxdart/rxdart.dart';
Stream<int> stream1 = Stream.fromIterable([1, 2, 3]);
Stream<String> stream2 = Stream.fromIterable(['a', 'b', 'c']);
Stream<List<dynamic>> combinedStream = Rx.combineLatest2(
stream1, stream2, (a, b) => [a, b]);
zip
method: This method merges the corresponding values emitted by each stream into a new stream. For example, if you have two streams of type int
and String
, and you want to combine them into a new stream with each emitted value as a list [int, String]
, you can use the following code:
import 'package:rxdart/rxdart.dart';
Stream<int> stream1 = Stream.fromIterable([1, 2, 3]);
Stream<String> stream2 = Stream.fromIterable(['a', 'b', 'c']);
Stream<List<dynamic>> combinedStream = Rx.zip2(
stream1, stream2, (a, b) => [a, b]);
Note: In both cases, the resulting Stream
is of type Stream<List<dynamic>>
, where dynamic
represents the type of values emitted by each original stream.