How can I leave the first argument of a function empty in Python if it has 2 optional arguments defined?

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You can use keyword arguments to leave the first argument empty while defining the second and/or the third arguments. Here is an example:

def my_function(first_arg="", second_arg=None, third_arg=None):
    print(f"First argument: {first_arg}")
    print(f"Second argument: {second_arg}")
    print(f"Third argument: {third_arg}")

# Calling the function with all arguments
my_function("Hello", True, 42)

# Calling the function with second and third arguments only
my_function(second_arg=False, third_arg=3.14)

Output:

First argument: Hello
Second argument: True
Third argument: 42

First argument: 
Second argument: False
Third argument: 3.14

As you can see, you can skip the first argument and provide values only for the second and/or third arguments using keyword arguments. If you don't specify the value for a keyword argument, it will take its default value (which is None in this case).