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How to generate a JSON parent in API DART?

asked 2023-01-06 11:00:00 +0000

plato gravatar image

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answered 2022-08-31 07:00:00 +0000

ladyg gravatar image

To generate a JSON parent in an API in Dart, you can define a class with the properties you want to include in the JSON object. You can then use the jsonEncode function from the dart:convert library to convert the class instance to JSON format.

Here's an example:

import 'dart:convert';

class Person {
  String name;
  int age;

  Person({required this.name, required this.age});

  Map<String, dynamic> toJson() {
    return {
      'name': name,
      'age': age,
    };
  }
}

void main() {
  Person person = Person(name: 'John', age: 30);
  String jsonStr = jsonEncode(person.toJson());
  print(jsonStr); // {"name":"John","age":30}
}

In this example, Person is defined as a class with two properties: name and age. The toJson method returns a Map<String, dynamic> object with the same properties as keys and their values.

When an instance of Person is created, it can be converted to a JSON string by calling jsonEncode with the result of toJson. The resulting string will have the same structure as the Map returned by toJson, with property names as keys and their values.

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Asked: 2023-01-06 11:00:00 +0000

Seen: 10 times

Last updated: Aug 31 '22