How to generate a list of all potential results for a sports league using Python?

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To generate a list of all potential results for a sports league using Python, you can use the itertools library to generate all possible combinations of game outcomes. Here's an example of how to generate all potential results for a league with 10 teams playing each other twice:

import itertools

teams = ['team1', 'team2', 'team3', 'team4', 'team5', 'team6', 'team7', 'team8', 'team9', 'team10']
games = list(itertools.combinations(teams, 2))
results = list(itertools.product([0, 1, 2], repeat=len(games)))

for result in results:
    standings = {team: {'wins': 0, 'ties': 0, 'losses': 0} for team in teams}
    for i, game in enumerate(games):
        home_team, away_team = game
        if result[i] == 0:  # home team wins
            standings[home_team]['wins'] += 1
            standings[away_team]['losses'] += 1
        elif result[i] == 1:  # tie
            standings[home_team]['ties'] += 1
            standings[away_team]['ties'] += 1
        elif result[i] == 2:  # away team wins
            standings[home_team]['losses'] += 1
            standings[away_team]['wins'] += 1
    sorted_standings = sorted(standings.items(), key=lambda x: x[1]['wins'], reverse=True)
    print(result, sorted_standings)

This code will generate a list of all possible results for the league, and print out the final standings for each result. The results list contains all possible combinations of 0, 1, and 2, where 0 represents a home team win, 1 represents a tie, and 2 represents an away team win.

For each result, the code uses a nested dictionary (standings) to keep track of each team's wins, ties, and losses. It then sorts the standings by the number of wins and prints out the final standings.