In order to transform a dictionary with a multidimensional array organized into groups into a struct, you would need to create a struct definition that reflects the same hierarchical organization as the dictionary. Each nested array would be defined as a property within the struct, and each group would be represented by a parent struct that contains the sub-structs that correspond to the nested arrays.
Once the struct definition is in place, you can loop through the dictionary and initialize each instance of the struct with the appropriate data. This would involve iterating through each group, creating a new instance of the parent struct for that group, and then iterating through each nested array within that group and initializing the appropriate property in the struct.
Here is an example of what the struct definition might look like for a dictionary with a structure like this:
{ "Group 1": { "Array 1": ["value1", "value2", "value3"], "Array 2": ["value4", "value5", "value6"] }, "Group 2": { "Array 3": ["value7", "value8", "value9"], "Array 4": ["value10", "value11", "value12"] } }
Assuming that the arrays are all of the same length, the struct definition might look like this:
struct MyStruct { var group1: Group1 var group2: Group2 }
struct Group1 { var array1: [String] var array2: [String] }
struct Group2 { var array3: [String] var array4: [String] }
Then, to initialize the struct from the dictionary, you could do something like this:
var myStruct = MyStruct( group1: Group1( array1: dictionary["Group 1"]!["Array 1"]!, array2: dictionary["Group 1"]!["Array 2"]! ), group2: Group2( array3: dictionary["Group 2"]!["Array 3"]!, array4: dictionary["Group 2"]!["Array 4"]! ) )
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Asked: 2023-06-26 06:58:10 +0000
Seen: 9 times
Last updated: Jun 26 '23
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