Can you find a subarray that adds up to a specific sum and has no interruptions in its sequence of elements?

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Yes, such a subarray is called a contiguous subarray. A simple algorithm to find a contiguous subarray that adds up to a specific sum is the sliding window technique:

1. Initialize two pointers, left and right, both pointing to the first element of the array.
2. Initialize a variable, sum, to 0.
3. Move the right pointer to the right until the sum of the elements between left and right is greater than or equal to the specific sum.
4. If the sum equals the specific sum, return the subarray from left to right.
5. Move the left pointer to the right until the sum is less than the specific sum.
6. Repeat steps 3-5 until the right pointer reaches the end of the array.

Here's the implementation of the algorithm in Python:

def find_contiguous_subarray(arr, target_sum):
    left, right = 0, 0
    sum = arr[left]

    while right < len(arr):
        if sum == target_sum:
            return arr[left:right+1]
        elif sum < target_sum:
            right += 1
            if right < len(arr):
                sum += arr[right]
        else:
            sum -= arr[left]
            left += 1

    return None

The function takes an array, arr, and a target sum, target_sum, as input and returns a contiguous subarray that adds up to the target sum. If no such subarray is found, it returns None.