It depends on the structure of the database and the data model. However, a possible SQL query to identify new customer IDs for each day could be:
SELECT DISTINCT currentday.customerid FROM customertable AS currentday LEFT JOIN customertable AS previousday ON currentday.customerid = previousday.customerid WHERE currentday.date = 'current date' AND previousday.date = 'previous date' AND previousday.customerid IS NULL;
This query uses a self-join to compare the customertable for the current day with the customertable for the previous day. The LEFT JOIN ensures that all customer IDs for the current day are included in the result, while the WHERE clause filters out those IDs that were already present in the previous day (i.e., where the previousday.customerid value is not null). The DISTINCT keyword eliminates any duplicate customer IDs in the result.
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Asked: 2023-06-25 00:35:27 +0000
Seen: 10 times
Last updated: Jun 25 '23
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