Can the lambda expression be evaluated as constexpr in C++17?

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Yes, in C++17, lambda expressions can be evaluated as constexpr under certain conditions. According to the C++17 standard, a lambda expression can be constexpr if:

1. The lambda body contains only the allowed statements and expressions that are allowed in a constexpr function.
2. The lambda captures do not include this, correferenced variables, or variables with non-literal types.
3. The lambda has no mutable or volatile qualifier.

If these conditions are met, the lambda can be declared as constexpr and evaluated at compile time.