In C++, why does the print statement free the value contained in a pointer?

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A print statement does not free the value contained in a pointer. It just outputs the value of the pointer or the value pointed to by the pointer. The memory allocated to a pointer is freed using the delete keyword or by going out of the scope where the pointer was declared, depending on how the memory was allocated. Improper use of delete, such as trying to delete a pointer multiple times or trying to delete a pointer to a stack-allocated variable, can result in memory leaks or other undefined behavior.