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What is the proper way to utilize "CreateHostBuilder(args).Build();" in .NET 6?

asked 2023-05-18 11:55:50 +0000

qstack gravatar image

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answered 2023-05-18 12:09:02 +0000

lakamha gravatar image

In .NET 6, the recommended way to use "CreateHostBuilder(args).Build();" is as follows:

  1. Start by creating a new console application using the .NET 6 template.

  2. Open the Program.cs file in the project and look for the Main method.

  3. Within the Main method, you should see a call to "CreateHostBuilder". This method creates a new instance of the host builder, which is responsible for managing the application's lifetime.

  4. After calling "CreateHostBuilder", you should chain a call to ".Build()" to build the host. This step is essential because it creates the host environment and configures services.

  5. Once the host has been built, you can start running your application. Typically, you would do this by calling the "Run()" method on the host object.

Here's an example of what this should look like:

using Microsoft.Extensions.Hosting;

namespace MyApp
{
    class Program
    {
        static void Main(string[] args)
        {
            CreateHostBuilder(args).Build().Run();
        }

        static IHostBuilder CreateHostBuilder(string[] args) =>
            Host.CreateDefaultBuilder(args)
                .ConfigureServices((hostContext, services) =>
                {
                    // configure services here
                });
    }
}

Note that this example uses the "Host.CreateDefaultBuilder" method, which is the most common way to set up a host builder. Additionally, you can add your own configuration and services as needed within the "ConfigureServices" callback. Finally, the "Run()" method is responsible for actually starting the application.

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Asked: 2023-05-18 11:55:50 +0000

Seen: 11 times

Last updated: May 18 '23