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How can I create a directory structure in s3 using Python and boto3?

asked 2022-12-10 11:00:00 +0000

ladyg gravatar image

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answered 2021-07-10 13:00:00 +0000

nofretete gravatar image

You can create a directory structure in S3 using Python and boto3 by the following steps:

  1. Import the boto3 library:
import boto3
  1. Create an S3 client:
s3 = boto3.client('s3')
  1. Define the bucket name:
bucket_name = 'your-bucket-name'
  1. Create a function to create a directory structure:
def create_directory_structure(directory_path):
    if not directory_path.endswith('/'):
        directory_path += '/'
    s3.put_object(Bucket=bucket_name, Key=(directory_path))

This function takes a directory path as an argument and then checks if the path ends with a forward slash "/". If not, it appends a forward slash to the end of the path. Then, it calls the put_object() method of the S3 client to create an empty object with the directory path as its key.

  1. Call the function to create directory structure:

This will create a directory structure in the S3 bucket with the following path: directory1/directory2/.

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Asked: 2022-12-10 11:00:00 +0000

Seen: 8 times

Last updated: Jul 10 '21