How can brackets in a filepath be managed when it is passed as a variable in the pipeline in Bash?

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When passing a file path that contains brackets as a variable in the pipeline in Bash, the brackets need to be escaped to ensure they are interpreted as part of the file path and not as part of the shell's syntax.

To escape brackets in a file path variable, use a backslash before each bracket character. For example:

file_path="/path/with/[brackets]/filename.txt"
echo $file_path | sed 's/\[\(.*\)\]/\1/' > output.txt

In this example, the sed command replaces the brackets with the content inside the brackets, effectively removing them from the file path. The backslashes before the brackets ensure that they are interpreted as part of the file path and not as part of the sed command's syntax.