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How come the expression $x=5; $x+++$x++; evaluates to 11 in PHP?

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• lua
• php

asked 2023-04-30 16:16:30 +0000

djk
21 ●1 ●1

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answered 2023-04-30 16:24:02 +0000

plato
56 ●5 ●5

It evaluates to 11 because the expression first increments $x by 1 (x++), then increments it again by 1 ($x++), and then adds the current value of $x to itself (5+6). So the final value of $x is 7 and the expression evaluates to 11.

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