Ask Your Question
3

How can I display only the output from tasks when using Ansible's debug function?

asked 2022-09-03 11:00:00 +0000

pufferfish gravatar image

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
1

answered 2023-01-24 02:00:00 +0000

lakamha gravatar image

You can use the msg parameter with the debug module to display only the output from tasks. For example:

- name: Print output from task
  debug:
    msg: "{{ output }}"
  vars:
    output: "{{ shell_command.stdout }}"
  become: true

In this example, the output of a shell command is stored in the output variable, and is then displayed using the msg parameter of the debug module. By using this approach, only the output from the specified task will be displayed.

edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account. This space is reserved only for answers. If you would like to engage in a discussion, please instead post a comment under the question or an answer that you would like to discuss

Add Answer


Question Tools

Stats

Asked: 2022-09-03 11:00:00 +0000

Seen: 7 times

Last updated: Jan 24 '23