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The error "TypeError: __init__() takes 1 positional argument but 5 were given" appears when attempting to create a table using pymysql. Can you offer a solution to this problem?

asked 2022-01-19 11:00:00 +0000

woof gravatar image

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answered 2022-10-14 22:00:00 +0000

djk gravatar image

The error message indicates that the init() method (constructor) of a class is expecting only one argument, but it is receiving five arguments instead. Based on the context of the problem, it seems like the error is related to creating a table using pymysql.

One possible solution to this problem is to check the arguments being passed to the init() method and make sure they match the expected parameters. In the case of pymysql, the suggested format for creating a table is:

CREATE TABLE table_name (
   column1 datatype constrains,
   column2 datatype constrains,
   ...
);

Make sure that the SQL syntax for creating a table is correct and it has the required parameters like table name, column names, datatypes, and constraints.

Additionally, make sure your SQL statement is a string and that you are using a cursor object to execute the query. Here's an example code snippet that shows how to create a table using pymysql:

import pymysql

# Open database connection
db = pymysql.connect("localhost","username","password","database_name")

# Prepare a cursor object
cursor = db.cursor()

# Create table SQL query
sql = """CREATE TABLE employee (
         emp_id INT(11) NOT NULL AUTO_INCREMENT,
         first_name VARCHAR(255),
         last_name VARCHAR(255),
         age INT(11),
         PRIMARY KEY (emp_id))"""

# Execute SQL query using cursor object
cursor.execute(sql)

# Commit changes to database
db.commit()

# Close database connection
db.close()

Hopefully, this solution helps you resolve the TypeError when creating a table using pymysql.

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Asked: 2022-01-19 11:00:00 +0000

Seen: 8 times

Last updated: Oct 14 '22