To launch files in custom applications using C# WinForms, you can use the Process.Start() method. Here's an example code:
private void btnLaunch_Click(object sender, EventArgs e)
{
string filePath = "C:\\folder\\file.exe"; // replace with your file path
string arguments = "argument1 argument2"; // replace with your arguments
ProcessStartInfo processInfo = new ProcessStartInfo(filePath, arguments);
processInfo.RedirectStandardOutput = true;
processInfo.UseShellExecute = false;
processInfo.CreateNoWindow = true;
Process process = new Process();
process.StartInfo = processInfo;
process.Start();
string output = process.StandardOutput.ReadToEnd();
Console.WriteLine(output);
}
In this code, you have to set the filePath variable to the location of your file, and the arguments variable to any arguments you want to pass to your custom application. The code then creates a ProcessStartInfo object with the file path and arguments, and sets some properties to redirect the standard output, disable the shell execution, and prevent the creation of a window. Finally, the code creates a Process object with the process info and starts the process. You can then read the output of the process if necessary.
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Asked: 2022-04-23 11:00:00 +0000
Seen: 7 times
Last updated: Sep 26 '21
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