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Bash: How can I grep all Lines with alphanumeric Character from a file and print them as Python Array?

asked 2023-04-07 22:30:01 +0000

qstack gravatar image

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answered 2023-04-07 22:30:06 +0000

qstack gravatar image

Here's an example of how to use grep and awk to filter alphanumeric lines from a file and print them as a Python array:

grep -E '^[a-zA-Z0-9]+$' file.txt | awk '{printf("\"%s\", ", $0)}' | sed 's/, $/\n/' | awk '{printf("[%s]", $0)}'

This command uses grep to filter the alphanumeric lines from file.txt by searching for lines that match the regular expression ^[a-zA-Z0-9]+$. The output of grep is then piped to the first awk command, which adds double quotes around each line to make it a valid string in Python. The output of this command is then piped to the second awk command, which uses printf to print the lines as a Python array in the format [ "line1", "line2", ... ].

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Asked: 2023-04-07 22:30:01 +0000

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Last updated: Apr 07