You can make Symfony 3 Console exception logging visible only on the console by modifying the Monolog configuration.
Open the config.yml
file in your Symfony project
Locate the Monolog configuration section. It should look something like this:
monolog:
handlers:
main:
type: stream
path: "%kernel.logs_dir%/%kernel.environment%.log"
level: debug
channels: [!event]
Add a new console
handler:
monolog:
handlers:
main:
type: stream
path: "%kernel.logs_dir%/%kernel.environment%.log"
level: debug
channels: [!event]
console:
type: console
process_psr_3_messages: false
channels: ["!event", "!doctrine"]
Save the file and run the Symfony console commands as usual. The exceptions will now only be visible on the console output.
The process_psr_3_messages
option is set to false
to prevent console messages from being duplicated in the log file. The channels
option tells Monolog which channels to log to the console. In this configuration, we're excluding the event
and doctrine
channels. Feel free to modify this setting based on your specific needs.
Please start posting anonymously - your entry will be published after you log in or create a new account. This space is reserved only for answers. If you would like to engage in a discussion, please instead post a comment under the question or an answer that you would like to discuss
Asked: 2021-04-07 11:00:00 +0000
Seen: 1 times
Last updated: Feb 09 '22
How can I deal with Expression.Error related to a column in Power Query?
How can you implement pagination in Oracle for the LISTAGG() function?
What is the process for implementing a FutureBuilder on an OnTap function in Flutter?
How can we require users to be logged in before they can access the root folders in WordPress?
In SCSS, what is the method for grouping and reusing a set of classes and styles?
How can popen() be used to direct streaming data to TAR?
How does iOS retrieve information from a BLE device?
How can Django Admin accommodate a variety of formats and locales for its input fields?