How can the color of a selected element (Picker) be modified in SwiftUI for WatchOS?

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To modify the color of a selected element (Picker) in SwiftUI for WatchOS, you can use the selectionStyle modifier. Here's an example:

struct ContentView: View {
    @State private var selectedColor = Color.red

    var body: some View {
        Picker("Color", selection: $selectedColor) {
            Text("Red").tag(Color.red)
            Text("Green").tag(Color.green)
            Text("Blue").tag(Color.blue)
        }
        .selectionStyle(.color(selectedColor))
    }
}

In this example, the selectedColor state variable is used to store the currently selected color. The Picker view has three options: red, green, and blue, and each one is tagged with its corresponding color. The selectionStyle modifier is then applied to the Picker view, with the .color style and the selectedColor variable passed in as parameters.

This will cause the selected color to be displayed as the background color of the selected option, making it clear which color is currently selected.